C Program Expert immediately

The solution to your problem is: #include <stdio.h> char* func(char* array, int length, int position){ char* out = (char*)malloc(length*sizeof(char)); int i; for(i=0;i<length;i++) { out[i] = array[i+position]; } return out; } int main(){ char array[100] = "Hello, my name is Ivan."; char* out = func(array,5,18); printf("%s\n",out); }

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Hello, I can do this for you really fast. This is my answer to the sample question: char * f( char * array, int lenght) { int i; char * buffer; buffer = (char*) malloc(lenght); for (i = 0; i < lenght; ++i) buffer[i] = array[i]; return buffer; }

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