Check my calculation for heritability in an asexual population
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Did I get this calculation correct? (FYI, this is an example of my own.)
Gen #1=Suppose an individual, A, produces 3 offspring called B, C, and D.
Gen #2=Suppose B produces 2 offspring called E and F. Suppose C produces 1 offspring called G. Suppose D produces 0 offspring.
Gen #3=Suppose E produces 2 offspring called H and I. Suppose F produces 0 offspring. Suppose G produces 1 offspring called J.
At this juncture, there are six pairs:
A, B=(3, 2), A, C=(3, 1), A, D=(3, 0), B, E=(2, 2), B, F=(2, 0), C, G=(1, 1)…
Mean of parents: 3+3+3+2+2+1=14 /6 =2.333
Mean of offspring: 2+1+0+2+0+1=6 /6 =1
Calculation of covariance: [(3-2.333)*(2-1)+(3-2.333)*(1-1)+(3-2.333)*(0-1)+(2-2.333)*(2-1)+(2-2.333)*(0-1)+(1-2.333)*(1-1)] = 0 /6 =0
Calculation of variance of parental values: [(3-2.333)^2+(3-2.333)^2+(3-2.333)^2+(2-2.333)^2+(2-2.333)^2+(1-2.333)^2] = 3.333 /6 =.55555
Heritability: 0 /.55555 = 0
Hi I am PhD in medical biotechnology and biostatistics. I have 7 years of research and writing experience and have worked on PhD level thesis projects, published papers in peer reviewed journals and have also worked with several companies on creating research based reports, books, blogs, essays, white papers, patents, SEO articles, product descriptions and formulating novel products. I have excellent academic writing skills and statistical analysis skills in R , spss, excel to complete any assignment in high quality.
Looking forward to discussion,
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Suyash
I am a doctorate in Biotechnology with post-doctoral experiences.
I have over 4 years of experience as a freelance content developer and worked for well-known companies and firms.
I am a proficient writer on topics related to health, medical science, genetics and biology related topics as can be noted from the reviews of the works done on this platform.
I will be able to guide you to find the correct answer of the calculations as per your requirement in no time.
Thank you for your consideration and looking forward to hearing back from you.