Exception Handling

Modify the following code to use exception handling, such that if the user enters in # a character string, such as "hello", the exception handling code will gracefully handle # the exception, tell the user what he/she did wrong, and continue to ask the user to # enter the correct number. # # Note: Do not use the isdigit() method with your answer. You should complete this # assignment using exception handling. USER_INPUT_MIN = 1 USER_INPUT_MAX = 20 def main() : answer = 0 while (answer < USER_INPUT_MIN or answer > USER_INPUT_MAX) : answer = int(input("Enter number: ")) if (answer < USER_INPUT_MIN or answer > USER_INPUT_MAX) : print("Please enter a number between %d and %d" % (USER_INPUT_MIN, USER_INPUT_MAX)) print("Got the user's answer: ", answer) main()